C151H228N40O47
1 compound has this formula on CompoundList.
- Molar mass
- 3355.72g/mol
- Monoisotopic mass
- 3353.6681Da
- Atoms
- 466
- Elements
- 4
- Rings plus double bonds
- 58
The formula C151H228N40O47 describes a molecule made of 151 carbon atoms, 228 hydrogen atoms, 40 nitrogen atoms and 47 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 15154.05%12.011 × 151 = 1813.661 g/mol
- H Hydrogen × 2286.85%1.008 × 228 = 229.824 g/mol
- N Nitrogen × 4016.70%14.007 × 40 = 560.280 g/mol
- O Oxygen × 4722.41%15.999 × 47 = 751.953 g/mol
Compounds with the formula C151H228N40O47
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C151H228N40O47?
The molar mass of C151H228N40O47 is 3355.72 g/mol, calculated from standard atomic weights for 151 carbon atoms, 228 hydrogen atoms, 40 nitrogen atoms and 47 oxygen atoms. The monoisotopic mass is 3353.6681 Da.
How many compounds have the formula C151H228N40O47?
CompoundList lists 1 compound with the molecular formula C151H228N40O47, including Glucagon-like peptide 1 (7-37). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C151H228N40O47?
C151H228N40O47 has a degree of unsaturation of 58. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.