CompoundList
Molecular formula

C15H14Cl2F3NO

7 compounds have this formula on CompoundList.

Molar mass
352.18g/mol
Monoisotopic mass
351.0405Da
Atoms
36
Elements
6
Rings plus double bonds
7

The formula C15H14Cl2F3NO describes a molecule made of 15 carbon atoms, 14 hydrogen atoms, 2 chlorine atoms, 3 fluorine atoms, 1 nitrogen atom and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1551.16%
    12.011 × 15 = 180.165 g/mol
  • H Hydrogen × 144.01%
    1.008 × 14 = 14.112 g/mol
  • Cl Chlorine × 220.13%
    35.45 × 2 = 70.900 g/mol
  • F Fluorine × 316.18%
    18.998 × 3 = 56.994 g/mol
  • N Nitrogen × 13.98%
    14.007 × 1 = 14.007 g/mol
  • O Oxygen × 14.54%
    15.999 × 1 = 15.999 g/mol
Look up another formula

Compounds with the formula C15H14Cl2F3NO

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 7 of 7 compounds

Frequently asked questions

What is the molar mass of C15H14Cl2F3NO?

The molar mass of C15H14Cl2F3NO is 352.18 g/mol, calculated from standard atomic weights for 15 carbon atoms, 14 hydrogen atoms, 2 chlorine atoms, 3 fluorine atoms, 1 nitrogen atom and 1 oxygen atom. The monoisotopic mass is 351.0405 Da.

How many compounds have the formula C15H14Cl2F3NO?

CompoundList lists 7 compounds with the molecular formula C15H14Cl2F3NO, including 3-(2,2-Dichlorovinyl)-2,2-dimethyl-N-[2-(trifluoromethyl)phenyl]cyclopropanecarboxamide, 2-(4-Chlorophenyl)-1-[4-(trifluoromethoxy)phenyl]ethan-1-amine hydrochloride, 4-(4-Chloro-3,5-dimethylphenoxy)-3-(trifluoromethyl)aniline hydrochloride. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C15H14Cl2F3NO?

C15H14Cl2F3NO has a degree of unsaturation of 7. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.