C15H15N2O7PS
3 compounds have this formula on CompoundList.
- Molar mass
- 398.33g/mol
- Monoisotopic mass
- 398.0338Da
- Atoms
- 41
- Elements
- 6
- Rings plus double bonds
- 10
The formula C15H15N2O7PS describes a molecule made of 15 carbon atoms, 15 hydrogen atoms, 2 nitrogen atoms, 7 oxygen atoms, 1 phosphorus atom and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1545.23%12.011 × 15 = 180.165 g/mol
- H Hydrogen × 153.80%1.008 × 15 = 15.120 g/mol
- N Nitrogen × 27.03%14.007 × 2 = 28.014 g/mol
- O Oxygen × 728.12%15.999 × 7 = 111.993 g/mol
- P Phosphorus × 17.78%30.974 × 1 = 30.974 g/mol
- S Sulfur × 18.05%32.06 × 1 = 32.060 g/mol
Compounds with the formula C15H15N2O7PS
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 3 of 3 compounds
Frequently asked questions
What is the molar mass of C15H15N2O7PS?
The molar mass of C15H15N2O7PS is 398.33 g/mol, calculated from standard atomic weights for 15 carbon atoms, 15 hydrogen atoms, 2 nitrogen atoms, 7 oxygen atoms, 1 phosphorus atom and 1 sulfur atom. The monoisotopic mass is 398.0338 Da.
How many compounds have the formula C15H15N2O7PS?
CompoundList lists 3 compounds with the molecular formula C15H15N2O7PS, including Bis-fenitrothion, Phosphorothioic acid, O,O-bis(4-nitrophenyl) S-(1-methylethyl) ester, Phosphorothioic acid, O,O-bis(4-nitrophenyl) O-propyl ester. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C15H15N2O7PS?
C15H15N2O7PS has a degree of unsaturation of 10. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.