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Molecular formula

C15H19N5O2S4

1 compound has this formula on CompoundList.

Molar mass
429.59g/mol
Monoisotopic mass
429.0422Da
Atoms
45
Elements
5
Rings plus double bonds
9

The formula C15H19N5O2S4 describes a molecule made of 15 carbon atoms, 19 hydrogen atoms, 5 nitrogen atoms, 2 oxygen atoms and 4 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1541.94%
    12.011 × 15 = 180.165 g/mol
  • H Hydrogen × 194.46%
    1.008 × 19 = 19.152 g/mol
  • N Nitrogen × 516.30%
    14.007 × 5 = 70.035 g/mol
  • O Oxygen × 27.45%
    15.999 × 2 = 31.998 g/mol
  • S Sulfur × 429.85%
    32.06 × 4 = 128.240 g/mol
Look up another formula

Compounds with the formula C15H19N5O2S4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

2-[(3-Ethyl-6-methyl-4-oxo-6,7-dihydrothieno[3,2-d]pyrimidin-2-yl)sulfanyl]-N-(5-ethylsulfanyl-1,3,4-thiadiazol-2-yl)acetamide chemical structure, C15H19N5O2S4, CAS 851409-27-3
2-[(3-Ethyl-6-methyl-4-oxo-6,7-dihydrothieno[3,2-d]pyrimidin-2-yl)sulfanyl]-N-(5-ethylsulfanyl-1,3,4-thiadiazol-2-yl)acetamide
CAS 851409-27-3C15H19N5O2S4

Frequently asked questions

What is the molar mass of C15H19N5O2S4?

The molar mass of C15H19N5O2S4 is 429.59 g/mol, calculated from standard atomic weights for 15 carbon atoms, 19 hydrogen atoms, 5 nitrogen atoms, 2 oxygen atoms and 4 sulfur atoms. The monoisotopic mass is 429.0422 Da.

How many compounds have the formula C15H19N5O2S4?

CompoundList lists 1 compound with the molecular formula C15H19N5O2S4, including 2-[(3-Ethyl-6-methyl-4-oxo-6,7-dihydrothieno[3,2-d]pyrimidin-2-yl)sulfanyl]-N-(5-ethylsulfanyl-1,3,4-thiadiazol-2-yl)acetamide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C15H19N5O2S4?

C15H19N5O2S4 has a degree of unsaturation of 9. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.