C15H23BO5
12 compounds have this formula on CompoundList.
- Molar mass
- 294.15g/mol
- Monoisotopic mass
- 294.1639Da
- Atoms
- 44
- Elements
- 4
The formula C15H23BO5 describes a molecule made of 15 carbon atoms, 23 hydrogen atoms, 1 boron atom and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1561.25%12.011 × 15 = 180.165 g/mol
- H Hydrogen × 237.88%1.008 × 23 = 23.184 g/mol
- B Boron × 13.67%10.81 × 1 = 10.810 g/mol
- O Oxygen × 527.19%15.999 × 5 = 79.995 g/mol
Compounds with the formula C15H23BO5
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 12 of 12 compounds
Frequently asked questions
What is the molar mass of C15H23BO5?
The molar mass of C15H23BO5 is 294.15 g/mol, calculated from standard atomic weights for 15 carbon atoms, 23 hydrogen atoms, 1 boron atom and 5 oxygen atoms. The monoisotopic mass is 294.1639 Da.
How many compounds have the formula C15H23BO5?
CompoundList lists 12 compounds with the molecular formula C15H23BO5, including 4,4,5,5-Tetramethyl-2-(2,4,6-trimethoxyphenyl)-1,3,2-dioxaborolane, 4,4,5,5-Tetramethyl-2-(3,4,5-trimethoxyphenyl)-1,3,2-dioxaborolane, 2-Methoxy-4-(methoxymethoxy)-phenylboronic acid pinacol ester. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.