C15H23FO2S
1 compound has this formula on CompoundList.
- Molar mass
- 286.40g/mol
- Monoisotopic mass
- 286.1403Da
- Atoms
- 42
- Elements
- 5
- Rings plus double bonds
- 4
The formula C15H23FO2S describes a molecule made of 15 carbon atoms, 23 hydrogen atoms, 1 fluorine atom, 2 oxygen atoms and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1562.91%12.011 × 15 = 180.165 g/mol
- H Hydrogen × 238.09%1.008 × 23 = 23.184 g/mol
- F Fluorine × 16.63%18.998 × 1 = 18.998 g/mol
- O Oxygen × 211.17%15.999 × 2 = 31.998 g/mol
- S Sulfur × 111.19%32.06 × 1 = 32.060 g/mol
Compounds with the formula C15H23FO2S
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C15H23FO2S?
The molar mass of C15H23FO2S is 286.40 g/mol, calculated from standard atomic weights for 15 carbon atoms, 23 hydrogen atoms, 1 fluorine atom, 2 oxygen atoms and 1 sulfur atom. The monoisotopic mass is 286.1403 Da.
How many compounds have the formula C15H23FO2S?
CompoundList lists 1 compound with the molecular formula C15H23FO2S, including 2,4,6-Tris(1-methylethyl)benzenesulfonyl fluoride. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C15H23FO2S?
C15H23FO2S has a degree of unsaturation of 4. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.