C15H24O6Pr
3 compounds have this formula on CompoundList.
- Molar mass
- 441.26g/mol
- Monoisotopic mass
- 441.0649Da
- Atoms
- 46
- Elements
- 4
The formula C15H24O6Pr describes a molecule made of 15 carbon atoms, 24 hydrogen atoms, 6 oxygen atoms and 1 praseodymium atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1540.83%12.011 × 15 = 180.165 g/mol
- H Hydrogen × 245.48%1.008 × 24 = 24.192 g/mol
- O Oxygen × 621.75%15.999 × 6 = 95.994 g/mol
- Pr Praseodymium × 131.93%140.91 × 1 = 140.910 g/mol
Compounds with the formula C15H24O6Pr
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 3 of 3 compounds
Frequently asked questions
What is the molar mass of C15H24O6Pr?
The molar mass of C15H24O6Pr is 441.26 g/mol, calculated from standard atomic weights for 15 carbon atoms, 24 hydrogen atoms, 6 oxygen atoms and 1 praseodymium atom. The monoisotopic mass is 441.0649 Da.
How many compounds have the formula C15H24O6Pr?
CompoundList lists 3 compounds with the molecular formula C15H24O6Pr, including Praseodymium(III) acetylacetonate hydrate, Praseodymium 2,4-pentanedionate, Tris(4-hydroxypent-3-en-2-one), praseodymium. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.