C15H28BF4P
1 compound has this formula on CompoundList.
- Molar mass
- 326.16g/mol
- Monoisotopic mass
- 326.1958Da
- Atoms
- 49
- Elements
- 5
The formula C15H28BF4P describes a molecule made of 15 carbon atoms, 28 hydrogen atoms, 1 boron atom, 4 fluorine atoms and 1 phosphorus atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1555.24%12.011 × 15 = 180.165 g/mol
- H Hydrogen × 288.65%1.008 × 28 = 28.224 g/mol
- B Boron × 13.31%10.81 × 1 = 10.810 g/mol
- F Fluorine × 423.30%18.998 × 4 = 75.992 g/mol
- P Phosphorus × 19.50%30.974 × 1 = 30.974 g/mol
Compounds with the formula C15H28BF4P
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C15H28BF4P?
The molar mass of C15H28BF4P is 326.16 g/mol, calculated from standard atomic weights for 15 carbon atoms, 28 hydrogen atoms, 1 boron atom, 4 fluorine atoms and 1 phosphorus atom. The monoisotopic mass is 326.1958 Da.
How many compounds have the formula C15H28BF4P?
CompoundList lists 1 compound with the molecular formula C15H28BF4P, including Tricyclopentylphosphine tetrafluoroborate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.