C15H31Br
10 compounds have this formula on CompoundList.
- Molar mass
- 291.32g/mol
- Monoisotopic mass
- 321.3555Da
- Atoms
- 47
- Elements
- 3
- Rings plus double bonds
- 0
The formula C15H31Br describes a molecule made of 15 carbon atoms, 31 hydrogen atoms and 1 bromine atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1561.85%12.011 × 15 = 180.165 g/mol
- H Hydrogen × 3110.73%1.008 × 31 = 31.248 g/mol
- Br Bromine × 127.43%79.904 × 1 = 79.904 g/mol
Compounds with the formula C15H31Br
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 10 of 10 compounds
Frequently asked questions
What is the molar mass of C15H31Br?
The molar mass of C15H31Br is 291.32 g/mol, calculated from standard atomic weights for 15 carbon atoms, 31 hydrogen atoms and 1 bromine atom. The monoisotopic mass is 321.3555 Da.
How many compounds have the formula C15H31Br?
CompoundList lists 10 compounds with the molecular formula C15H31Br, including 1-Bromopentadecane, 1-Bromo-3,7,11-trimethyldodecane, 1-Bromopentadecane-D31. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C15H31Br?
C15H31Br has a degree of unsaturation of 0. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.