C15H31O9P3
1 compound has this formula on CompoundList.
- Molar mass
- 448.33g/mol
- Monoisotopic mass
- 448.1181Da
- Atoms
- 58
- Elements
- 4
- Rings plus double bonds
- 2
The formula C15H31O9P3 describes a molecule made of 15 carbon atoms, 31 hydrogen atoms, 9 oxygen atoms and 3 phosphorus atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1540.19%12.011 × 15 = 180.165 g/mol
- H Hydrogen × 316.97%1.008 × 31 = 31.248 g/mol
- O Oxygen × 932.12%15.999 × 9 = 143.991 g/mol
- P Phosphorus × 320.73%30.974 × 3 = 92.922 g/mol
Compounds with the formula C15H31O9P3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C15H31O9P3?
The molar mass of C15H31O9P3 is 448.33 g/mol, calculated from standard atomic weights for 15 carbon atoms, 31 hydrogen atoms, 9 oxygen atoms and 3 phosphorus atoms. The monoisotopic mass is 448.1181 Da.
How many compounds have the formula C15H31O9P3?
CompoundList lists 1 compound with the molecular formula C15H31O9P3, including Bis((5-ethyl-2-methyl-1,3,2-dioxaphosphorinan-5-yl)methyl) methyl phosphonate P,P'-dioxide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C15H31O9P3?
C15H31O9P3 has a degree of unsaturation of 2. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.