CompoundList
Molecular formula

C15H9Cl3O

17 compounds have this formula on CompoundList.

Molar mass
311.59g/mol
Monoisotopic mass
309.9719Da
Atoms
28
Elements
4
Rings plus double bonds
10

The formula C15H9Cl3O describes a molecule made of 15 carbon atoms, 9 hydrogen atoms, 3 chlorine atoms and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1557.82%
    12.011 × 15 = 180.165 g/mol
  • H Hydrogen × 92.91%
    1.008 × 9 = 9.072 g/mol
  • Cl Chlorine × 334.13%
    35.45 × 3 = 106.350 g/mol
  • O Oxygen × 15.13%
    15.999 × 1 = 15.999 g/mol
Look up another formula

Compounds with the formula C15H9Cl3O

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 17 of 17 compounds

Frequently asked questions

What is the molar mass of C15H9Cl3O?

The molar mass of C15H9Cl3O is 311.59 g/mol, calculated from standard atomic weights for 15 carbon atoms, 9 hydrogen atoms, 3 chlorine atoms and 1 oxygen atom. The monoisotopic mass is 309.9719 Da.

How many compounds have the formula C15H9Cl3O?

CompoundList lists 17 compounds with the molecular formula C15H9Cl3O, including 2,4,4'-Trichlorochalcone, 2-Propen-1-one, 1-(4-chlorophenyl)-3-(2,6-dichlorophenyl)-, 2-Chloro-1-(2,7-dichloro-9H-fluoren-4-yl)ethanone. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C15H9Cl3O?

C15H9Cl3O has a degree of unsaturation of 10. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.