C160H194N22O54S4
1 compound has this formula on CompoundList.
- Molar mass
- 3417.65g/mol
- Monoisotopic mass
- 3415.1994Da
- Atoms
- 434
- Elements
- 5
- Rings plus double bonds
- 75
The formula C160H194N22O54S4 describes a molecule made of 160 carbon atoms, 194 hydrogen atoms, 22 nitrogen atoms, 54 oxygen atoms and 4 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 16056.23%12.011 × 160 = 1921.760 g/mol
- H Hydrogen × 1945.72%1.008 × 194 = 195.552 g/mol
- N Nitrogen × 229.02%14.007 × 22 = 308.154 g/mol
- O Oxygen × 5425.28%15.999 × 54 = 863.946 g/mol
- S Sulfur × 43.75%32.06 × 4 = 128.240 g/mol
Compounds with the formula C160H194N22O54S4
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C160H194N22O54S4?
The molar mass of C160H194N22O54S4 is 3417.65 g/mol, calculated from standard atomic weights for 160 carbon atoms, 194 hydrogen atoms, 22 nitrogen atoms, 54 oxygen atoms and 4 sulfur atoms. The monoisotopic mass is 3415.1994 Da.
How many compounds have the formula C160H194N22O54S4?
CompoundList lists 1 compound with the molecular formula C160H194N22O54S4, including Prolactin. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C160H194N22O54S4?
C160H194N22O54S4 has a degree of unsaturation of 75. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.