C16H15FN4O5
3 compounds have this formula on CompoundList.
- Molar mass
- 362.32g/mol
- Monoisotopic mass
- 362.1026Da
- Atoms
- 41
- Elements
- 5
- Rings plus double bonds
- 11
The formula C16H15FN4O5 describes a molecule made of 16 carbon atoms, 15 hydrogen atoms, 1 fluorine atom, 4 nitrogen atoms and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1653.04%12.011 × 16 = 192.176 g/mol
- H Hydrogen × 154.17%1.008 × 15 = 15.120 g/mol
- F Fluorine × 15.24%18.998 × 1 = 18.998 g/mol
- N Nitrogen × 415.46%14.007 × 4 = 56.028 g/mol
- O Oxygen × 522.08%15.999 × 5 = 79.995 g/mol
Compounds with the formula C16H15FN4O5
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 3 of 3 compounds
![N-[4-(2-Fluoro-4-nitrophenoxy)pyridin-2-yl]morpholine-4-carboxamide chemical structure, C16H15FN4O5, CAS 864245-86-3](/s/PXCLOBPSDSYDFW-UHFFFAOYSA-N.svg)
![N-{[3-(2-Fluorophenyl)-6-oxopyridazin-1(6H)-yl]acetyl}glycylglycine chemical structure, C16H15FN4O5, CAS 1246069-14-6](/s/JXAZLRRHJQKZIL-UHFFFAOYSA-N.svg)
![N-{[3-(4-Fluorophenyl)-6-oxopyridazin-1(6H)-yl]acetyl}glycylglycine chemical structure, C16H15FN4O5, CAS 1246066-87-4](/s/RLXFXJIAHMJWNS-UHFFFAOYSA-N.svg)
Frequently asked questions
What is the molar mass of C16H15FN4O5?
The molar mass of C16H15FN4O5 is 362.32 g/mol, calculated from standard atomic weights for 16 carbon atoms, 15 hydrogen atoms, 1 fluorine atom, 4 nitrogen atoms and 5 oxygen atoms. The monoisotopic mass is 362.1026 Da.
How many compounds have the formula C16H15FN4O5?
CompoundList lists 3 compounds with the molecular formula C16H15FN4O5, including N-[4-(2-Fluoro-4-nitrophenoxy)pyridin-2-yl]morpholine-4-carboxamide, N-{[3-(2-Fluorophenyl)-6-oxopyridazin-1(6H)-yl]acetyl}glycylglycine, N-{[3-(4-Fluorophenyl)-6-oxopyridazin-1(6H)-yl]acetyl}glycylglycine. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C16H15FN4O5?
C16H15FN4O5 has a degree of unsaturation of 11. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.