CompoundList
Molecular formula

C16H16ClF2NO2

1 compound has this formula on CompoundList.

Molar mass
327.75g/mol
Monoisotopic mass
327.0838Da
Atoms
38
Elements
6
Rings plus double bonds
8

The formula C16H16ClF2NO2 describes a molecule made of 16 carbon atoms, 16 hydrogen atoms, 1 chlorine atom, 2 fluorine atoms, 1 nitrogen atom and 2 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1658.63%
    12.011 × 16 = 192.176 g/mol
  • H Hydrogen × 164.92%
    1.008 × 16 = 16.128 g/mol
  • Cl Chlorine × 110.82%
    35.45 × 1 = 35.450 g/mol
  • F Fluorine × 211.59%
    18.998 × 2 = 37.996 g/mol
  • N Nitrogen × 14.27%
    14.007 × 1 = 14.007 g/mol
  • O Oxygen × 29.76%
    15.999 × 2 = 31.998 g/mol
Look up another formula

Compounds with the formula C16H16ClF2NO2

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C16H16ClF2NO2?

The molar mass of C16H16ClF2NO2 is 327.75 g/mol, calculated from standard atomic weights for 16 carbon atoms, 16 hydrogen atoms, 1 chlorine atom, 2 fluorine atoms, 1 nitrogen atom and 2 oxygen atoms. The monoisotopic mass is 327.0838 Da.

How many compounds have the formula C16H16ClF2NO2?

CompoundList lists 1 compound with the molecular formula C16H16ClF2NO2, including 2-Chloro-1-(1-(4-(difluoromethoxy)phenyl)-2,5-dimethyl-1H-pyrrol-3-yl)propan-1-one. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C16H16ClF2NO2?

C16H16ClF2NO2 has a degree of unsaturation of 8. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.