CompoundList
Molecular formula

C16H37N3O4

1 compound has this formula on CompoundList.

Molar mass
335.49g/mol
Monoisotopic mass
335.2784Da
Atoms
60
Elements
4
Rings plus double bonds
0

The formula C16H37N3O4 describes a molecule made of 16 carbon atoms, 37 hydrogen atoms, 3 nitrogen atoms and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1657.28%
    12.011 × 16 = 192.176 g/mol
  • H Hydrogen × 3711.12%
    1.008 × 37 = 37.296 g/mol
  • N Nitrogen × 312.53%
    14.007 × 3 = 42.021 g/mol
  • O Oxygen × 419.08%
    15.999 × 4 = 63.996 g/mol
Look up another formula

Compounds with the formula C16H37N3O4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C16H37N3O4?

The molar mass of C16H37N3O4 is 335.49 g/mol, calculated from standard atomic weights for 16 carbon atoms, 37 hydrogen atoms, 3 nitrogen atoms and 4 oxygen atoms. The monoisotopic mass is 335.2784 Da.

How many compounds have the formula C16H37N3O4?

CompoundList lists 1 compound with the molecular formula C16H37N3O4, including 2-Propanol, 1,1',1'',1'''-[iminobis(2,1-ethanediylnitrilo)]tetrakis-. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C16H37N3O4?

C16H37N3O4 has a degree of unsaturation of 0. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.