C176H277N57O55S7
1 compound has this formula on CompoundList.
- Molar mass
- 4295.92g/mol
- Monoisotopic mass
- 4292.8676Da
- Atoms
- 572
- Elements
- 5
- Rings plus double bonds
- 67
The formula C176H277N57O55S7 describes a molecule made of 176 carbon atoms, 277 hydrogen atoms, 57 nitrogen atoms, 55 oxygen atoms and 7 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 17649.21%12.011 × 176 = 2113.936 g/mol
- H Hydrogen × 2776.50%1.008 × 277 = 279.216 g/mol
- N Nitrogen × 5718.59%14.007 × 57 = 798.399 g/mol
- O Oxygen × 5520.48%15.999 × 55 = 879.945 g/mol
- S Sulfur × 75.22%32.06 × 7 = 224.420 g/mol
Compounds with the formula C176H277N57O55S7
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C176H277N57O55S7?
The molar mass of C176H277N57O55S7 is 4295.92 g/mol, calculated from standard atomic weights for 176 carbon atoms, 277 hydrogen atoms, 57 nitrogen atoms, 55 oxygen atoms and 7 sulfur atoms. The monoisotopic mass is 4292.8676 Da.
How many compounds have the formula C176H277N57O55S7?
CompoundList lists 1 compound with the molecular formula C176H277N57O55S7, including Charybdotoxin. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C176H277N57O55S7?
C176H277N57O55S7 has a degree of unsaturation of 67. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.