C17H10ClF3O4
1 compound has this formula on CompoundList.
- Molar mass
- 370.71g/mol
- Monoisotopic mass
- 370.0220Da
- Atoms
- 35
- Elements
- 5
- Rings plus double bonds
- 11
The formula C17H10ClF3O4 describes a molecule made of 17 carbon atoms, 10 hydrogen atoms, 1 chlorine atom, 3 fluorine atoms and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1755.08%12.011 × 17 = 204.187 g/mol
- H Hydrogen × 102.72%1.008 × 10 = 10.080 g/mol
- Cl Chlorine × 19.56%35.45 × 1 = 35.450 g/mol
- F Fluorine × 315.37%18.998 × 3 = 56.994 g/mol
- O Oxygen × 417.26%15.999 × 4 = 63.996 g/mol
Compounds with the formula C17H10ClF3O4
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C17H10ClF3O4?
The molar mass of C17H10ClF3O4 is 370.71 g/mol, calculated from standard atomic weights for 17 carbon atoms, 10 hydrogen atoms, 1 chlorine atom, 3 fluorine atoms and 4 oxygen atoms. The monoisotopic mass is 370.0220 Da.
How many compounds have the formula C17H10ClF3O4?
CompoundList lists 1 compound with the molecular formula C17H10ClF3O4, including 3-(4-Chloro-3-methylphenoxy)-7-hydroxy-2-(trifluoromethyl)-4H-chromen-4-one. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C17H10ClF3O4?
C17H10ClF3O4 has a degree of unsaturation of 11. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.