CompoundList
Molecular formula

C17H13IO4

7 compounds have this formula on CompoundList.

Molar mass
408.19g/mol
Monoisotopic mass
407.9859Da
Atoms
35
Elements
4
Rings plus double bonds
11

The formula C17H13IO4 describes a molecule made of 17 carbon atoms, 13 hydrogen atoms, 1 iodine atom and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1750.02%
    12.011 × 17 = 204.187 g/mol
  • H Hydrogen × 133.21%
    1.008 × 13 = 13.104 g/mol
  • I Iodine × 131.09%
    126.9 × 1 = 126.900 g/mol
  • O Oxygen × 415.68%
    15.999 × 4 = 63.996 g/mol
Look up another formula

Compounds with the formula C17H13IO4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 7 of 7 compounds

Frequently asked questions

What is the molar mass of C17H13IO4?

The molar mass of C17H13IO4 is 408.19 g/mol, calculated from standard atomic weights for 17 carbon atoms, 13 hydrogen atoms, 1 iodine atom and 4 oxygen atoms. The monoisotopic mass is 407.9859 Da.

How many compounds have the formula C17H13IO4?

CompoundList lists 7 compounds with the molecular formula C17H13IO4, including Methyl 2-(cinnamoyloxy)-5-iodobenzoate, 3-Iodo-6,7-dimethoxy-2-phenyl-chromen-4-one, 4H-1-Benzopyran-4-one, 2-(3,4-dimethoxyphenyl)-3-iodo-. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C17H13IO4?

C17H13IO4 has a degree of unsaturation of 11. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.