C17H14ClFN4OS
8 compounds have this formula on CompoundList.
- Molar mass
- 376.83g/mol
- Monoisotopic mass
- 376.0561Da
- Atoms
- 39
- Elements
- 7
- Rings plus double bonds
- 12
The formula C17H14ClFN4OS describes a molecule made of 17 carbon atoms, 14 hydrogen atoms, 1 chlorine atom, 1 fluorine atom, 4 nitrogen atoms, 1 oxygen atom and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1754.18%12.011 × 17 = 204.187 g/mol
- H Hydrogen × 143.74%1.008 × 14 = 14.112 g/mol
- Cl Chlorine × 19.41%35.45 × 1 = 35.450 g/mol
- F Fluorine × 15.04%18.998 × 1 = 18.998 g/mol
- N Nitrogen × 414.87%14.007 × 4 = 56.028 g/mol
- O Oxygen × 14.25%15.999 × 1 = 15.999 g/mol
- S Sulfur × 18.51%32.06 × 1 = 32.060 g/mol
Compounds with the formula C17H14ClFN4OS
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 8 of 8 compounds
Frequently asked questions
What is the molar mass of C17H14ClFN4OS?
The molar mass of C17H14ClFN4OS is 376.83 g/mol, calculated from standard atomic weights for 17 carbon atoms, 14 hydrogen atoms, 1 chlorine atom, 1 fluorine atom, 4 nitrogen atoms, 1 oxygen atom and 1 sulfur atom. The monoisotopic mass is 376.0561 Da.
How many compounds have the formula C17H14ClFN4OS?
CompoundList lists 8 compounds with the molecular formula C17H14ClFN4OS, including 4-((2-CL-6-Fluorobenzylidene)amino)-5-(3-ethoxyphenyl)-4H-1,2,4-triazole-3-thiol, 2-Chloro-6-fluoro-N-((5-thioxo-4-(m-tolyl)-4,5-dihydro-1H-1,2,4-triazol-3-yl)methyl)benzamide, 2-[[5-(4-Chlorophenyl)-4-methyl-1,2,4-triazol-3-yl]sulfanyl]-N-(3-fluorophenyl)acetamide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C17H14ClFN4OS?
C17H14ClFN4OS has a degree of unsaturation of 12. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.