C17H15FO4
35 compounds have this formula on CompoundList.
- Molar mass
- 302.30g/mol
- Monoisotopic mass
- 302.0954Da
- Atoms
- 37
- Elements
- 4
- Rings plus double bonds
- 10
The formula C17H15FO4 describes a molecule made of 17 carbon atoms, 15 hydrogen atoms, 1 fluorine atom and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1767.54%12.011 × 17 = 204.187 g/mol
- H Hydrogen × 155.00%1.008 × 15 = 15.120 g/mol
- F Fluorine × 16.28%18.998 × 1 = 18.998 g/mol
- O Oxygen × 421.17%15.999 × 4 = 63.996 g/mol
Compounds with the formula C17H15FO4
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 35 of 35 compounds
- Ethyl 2-(4-(benzyloxy)-3-fluorophenyl)-2-oxoacetate1898341-34-8C17H15FO4
- 3-(2,3-Dihydro-1,4-benzodioxin-6-yl)-2-(4-fluorophenyl)propanoic acid1225973-07-8C17H15FO4
- 2-[3-(4-Fluorobenzoyl)phenoxy]-2-methylpropanoic acid62809-84-1C17H15FO4
- Methyl 2-fluoro-5-[3-(2-methoxy-2-oxoethyl)phenyl]benzoate1820674-15-4C17H15FO4
- Methyl 3-fluoro-5-[3-(2-methoxy-2-oxoethyl)phenyl]benzoate1820640-49-0C17H15FO4
- 5-Acetyl-2-(3-fluoro-benzyloxy)-benzoic acid methyl ester1416345-10-2C17H15FO4
- 5-Acetyl-2-(4-fluoro-benzyloxy)-benzoic acid methyl ester1416344-15-4C17H15FO4
- 6-(Ethoxycarbonyl)-2'-fluoro-3'-methyl-[1,1'-biphenyl]-2-carboxylic acid3078361-11-9C17H15FO4
- 6-(Ethoxycarbonyl)-2'-fluoro-4'-methyl-[1,1'-biphenyl]-2-carboxylic acid3078383-96-4C17H15FO4
- 6-(Ethoxycarbonyl)-2'-fluoro-5'-methyl-[1,1'-biphenyl]-2-carboxylic acid3078381-78-6C17H15FO4
- (E)-3-(3,5-Dimethoxyphenyl)-2-(4-fluorophenyl)prop-2-enoic acid959961-12-7C17H15FO4
Frequently asked questions
What is the molar mass of C17H15FO4?
The molar mass of C17H15FO4 is 302.30 g/mol, calculated from standard atomic weights for 17 carbon atoms, 15 hydrogen atoms, 1 fluorine atom and 4 oxygen atoms. The monoisotopic mass is 302.0954 Da.
How many compounds have the formula C17H15FO4?
CompoundList lists 35 compounds with the molecular formula C17H15FO4, including 2-(4-Fluorophenyl)-4-(3-methoxyphenyl)-4-oxobutanoic acid, 4',6'-Dimethoxy-4-fluoro-2'-hydroxychalcone, (E)-1-(3-Fluoro-4-methoxyphenyl)-3-(4-hydroxy-3-methoxyphenyl)prop-2-en-1-one. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C17H15FO4?
C17H15FO4 has a degree of unsaturation of 10. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.