CompoundList
Molecular formula

C17H23BO5

9 compounds have this formula on CompoundList.

Molar mass
318.18g/mol
Monoisotopic mass
318.1639Da
Atoms
46
Elements
4

The formula C17H23BO5 describes a molecule made of 17 carbon atoms, 23 hydrogen atoms, 1 boron atom and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1764.17%
    12.011 × 17 = 204.187 g/mol
  • H Hydrogen × 237.29%
    1.008 × 23 = 23.184 g/mol
  • B Boron × 13.40%
    10.81 × 1 = 10.810 g/mol
  • O Oxygen × 525.14%
    15.999 × 5 = 79.995 g/mol
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Compounds with the formula C17H23BO5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 9 of 9 compounds

Frequently asked questions

What is the molar mass of C17H23BO5?

The molar mass of C17H23BO5 is 318.18 g/mol, calculated from standard atomic weights for 17 carbon atoms, 23 hydrogen atoms, 1 boron atom and 5 oxygen atoms. The monoisotopic mass is 318.1639 Da.

How many compounds have the formula C17H23BO5?

CompoundList lists 9 compounds with the molecular formula C17H23BO5, including 2-Methoxycarbonyl-3,4-dihydro-2H-benzopyran-6-boronic acid pinacol ester, 5-Cyclopropylmethoxy-4-(4,4,5,5-tetramethyl-[1,3,2]dioxaborolan-2-yl)-benzo[1,3]dioxole, Methyl 3-[4-(4,4,5,5-tetramethyl-1,3,2-dioxaborolan-2-yl)phenyl]oxetane-3-carboxylate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.