CompoundList
Molecular formula

C17H28BNO4

9 compounds have this formula on CompoundList.

Molar mass
321.22g/mol
Monoisotopic mass
321.2111Da
Atoms
51
Elements
5

The formula C17H28BNO4 describes a molecule made of 17 carbon atoms, 28 hydrogen atoms, 1 boron atom, 1 nitrogen atom and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1763.57%
    12.011 × 17 = 204.187 g/mol
  • H Hydrogen × 288.79%
    1.008 × 28 = 28.224 g/mol
  • B Boron × 13.37%
    10.81 × 1 = 10.810 g/mol
  • N Nitrogen × 14.36%
    14.007 × 1 = 14.007 g/mol
  • O Oxygen × 419.92%
    15.999 × 4 = 63.996 g/mol
Look up another formula

Compounds with the formula C17H28BNO4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 9 of 9 compounds

Frequently asked questions

What is the molar mass of C17H28BNO4?

The molar mass of C17H28BNO4 is 321.22 g/mol, calculated from standard atomic weights for 17 carbon atoms, 28 hydrogen atoms, 1 boron atom, 1 nitrogen atom and 4 oxygen atoms. The monoisotopic mass is 321.2111 Da.

How many compounds have the formula C17H28BNO4?

CompoundList lists 9 compounds with the molecular formula C17H28BNO4, including tert-Butyl 6-(4,4,5,5-tetramethyl-1,3,2-dioxaborolan-2-yl)-2-azaspiro[3.3]hept-5-ene-2-carboxylate, {[2,6-Dimethoxy-4-(tetramethyl-1,3,2-dioxaborolan-2-yl)phenyl]methyl}-dimethylamine, 2-Ethoxy-3-isobutoxy-5-(4,4,5,5-tetramethyl-1,3,2-dioxaborolan-2-yl)pyridine. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.