C189H287N49O55S5
1 compound has this formula on CompoundList.
- Molar mass
- 4285.96g/mol
- Monoisotopic mass
- 4282.9771Da
- Atoms
- 585
- Elements
- 5
- Rings plus double bonds
- 71
The formula C189H287N49O55S5 describes a molecule made of 189 carbon atoms, 287 hydrogen atoms, 49 nitrogen atoms, 55 oxygen atoms and 5 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 18952.97%12.011 × 189 = 2270.079 g/mol
- H Hydrogen × 2876.75%1.008 × 287 = 289.296 g/mol
- N Nitrogen × 4916.01%14.007 × 49 = 686.343 g/mol
- O Oxygen × 5520.53%15.999 × 55 = 879.945 g/mol
- S Sulfur × 53.74%32.06 × 5 = 160.300 g/mol
Compounds with the formula C189H287N49O55S5
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C189H287N49O55S5?
The molar mass of C189H287N49O55S5 is 4285.96 g/mol, calculated from standard atomic weights for 189 carbon atoms, 287 hydrogen atoms, 49 nitrogen atoms, 55 oxygen atoms and 5 sulfur atoms. The monoisotopic mass is 4282.9771 Da.
How many compounds have the formula C189H287N49O55S5?
CompoundList lists 1 compound with the molecular formula C189H287N49O55S5, including Big et-1 (1-38) (human). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C189H287N49O55S5?
C189H287N49O55S5 has a degree of unsaturation of 71. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.