CompoundList
Molecular formula

C18H13FN4

9 compounds have this formula on CompoundList.

Molar mass
304.33g/mol
Monoisotopic mass
304.1124Da
Atoms
36
Elements
4
Rings plus double bonds
14

The formula C18H13FN4 describes a molecule made of 18 carbon atoms, 13 hydrogen atoms, 1 fluorine atom and 4 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1871.04%
    12.011 × 18 = 216.198 g/mol
  • H Hydrogen × 134.31%
    1.008 × 13 = 13.104 g/mol
  • F Fluorine × 16.24%
    18.998 × 1 = 18.998 g/mol
  • N Nitrogen × 418.41%
    14.007 × 4 = 56.028 g/mol
Look up another formula

Compounds with the formula C18H13FN4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 9 of 9 compounds

Frequently asked questions

What is the molar mass of C18H13FN4?

The molar mass of C18H13FN4 is 304.33 g/mol, calculated from standard atomic weights for 18 carbon atoms, 13 hydrogen atoms, 1 fluorine atom and 4 nitrogen atoms. The monoisotopic mass is 304.1124 Da.

How many compounds have the formula C18H13FN4?

CompoundList lists 9 compounds with the molecular formula C18H13FN4, including 2-Amino-6-(4-fluorophenyl)-5-methyl-4-pyridin-3-ylpyridine-3-carbonitrile, 6-Amino-3-(pyridin-4-yl)-2-(4-fluorophenyl)-7-azaindole, 1,2,4-Triazolo(4,3-b)pyridazine, 6-(4-fluorophenyl)-3-methyl-8-phenyl-. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C18H13FN4?

C18H13FN4 has a degree of unsaturation of 14. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.