CompoundList
Molecular formula

C18H17ClFN3O3

10 compounds have this formula on CompoundList.

Molar mass
377.80g/mol
Monoisotopic mass
377.0942Da
Atoms
43
Elements
6
Rings plus double bonds
11

The formula C18H17ClFN3O3 describes a molecule made of 18 carbon atoms, 17 hydrogen atoms, 1 chlorine atom, 1 fluorine atom, 3 nitrogen atoms and 3 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1857.23%
    12.011 × 18 = 216.198 g/mol
  • H Hydrogen × 174.54%
    1.008 × 17 = 17.136 g/mol
  • Cl Chlorine × 19.38%
    35.45 × 1 = 35.450 g/mol
  • F Fluorine × 15.03%
    18.998 × 1 = 18.998 g/mol
  • N Nitrogen × 311.12%
    14.007 × 3 = 42.021 g/mol
  • O Oxygen × 312.70%
    15.999 × 3 = 47.997 g/mol
Look up another formula

Compounds with the formula C18H17ClFN3O3

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 10 of 10 compounds

Frequently asked questions

What is the molar mass of C18H17ClFN3O3?

The molar mass of C18H17ClFN3O3 is 377.80 g/mol, calculated from standard atomic weights for 18 carbon atoms, 17 hydrogen atoms, 1 chlorine atom, 1 fluorine atom, 3 nitrogen atoms and 3 oxygen atoms. The monoisotopic mass is 377.0942 Da.

How many compounds have the formula C18H17ClFN3O3?

CompoundList lists 10 compounds with the molecular formula C18H17ClFN3O3, including 3-(2-Chloro-6-fluorobenzyl)-5-ethoxy-1,6-dimethylpyrido[2,3-d]pyrimidine-2,4(1H,3H)-dione, N-(2-(4-Acetamidobenzamido)ethyl)-2-chloro-6-fluorobenzamide, [4-[(2-Chloro-4-fluorophenyl)methyl]piperazin-1-yl]-(2-nitrophenyl)methanone. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C18H17ClFN3O3?

C18H17ClFN3O3 has a degree of unsaturation of 11. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.