C192H206F4N14O18
1 compound has this formula on CompoundList.
- Molar mass
- 3073.83g/mol
- Monoisotopic mass
- 3071.5571Da
- Atoms
- 434
- Elements
- 5
- Rings plus double bonds
- 95
The formula C192H206F4N14O18 describes a molecule made of 192 carbon atoms, 206 hydrogen atoms, 4 fluorine atoms, 14 nitrogen atoms and 18 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 19275.02%12.011 × 192 = 2306.112 g/mol
- H Hydrogen × 2066.76%1.008 × 206 = 207.648 g/mol
- F Fluorine × 42.47%18.998 × 4 = 75.992 g/mol
- N Nitrogen × 146.38%14.007 × 14 = 196.098 g/mol
- O Oxygen × 189.37%15.999 × 18 = 287.982 g/mol
Compounds with the formula C192H206F4N14O18
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C192H206F4N14O18?
The molar mass of C192H206F4N14O18 is 3073.83 g/mol, calculated from standard atomic weights for 192 carbon atoms, 206 hydrogen atoms, 4 fluorine atoms, 14 nitrogen atoms and 18 oxygen atoms. The monoisotopic mass is 3071.5571 Da.
How many compounds have the formula C192H206F4N14O18?
CompoundList lists 1 compound with the molecular formula C192H206F4N14O18, including Fructose-bisphosphate aldolase. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C192H206F4N14O18?
C192H206F4N14O18 has a degree of unsaturation of 95. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.