C197H325N53O55
1 compound has this formula on CompoundList.
- Molar mass
- 4316.08g/mol
- Monoisotopic mass
- 4313.4264Da
- Atoms
- 630
- Elements
- 4
- Rings plus double bonds
- 62
The formula C197H325N53O55 describes a molecule made of 197 carbon atoms, 325 hydrogen atoms, 53 nitrogen atoms and 55 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 19754.82%12.011 × 197 = 2366.167 g/mol
- H Hydrogen × 3257.59%1.008 × 325 = 327.600 g/mol
- N Nitrogen × 5317.20%14.007 × 53 = 742.371 g/mol
- O Oxygen × 5520.39%15.999 × 55 = 879.945 g/mol
Compounds with the formula C197H325N53O55
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C197H325N53O55?
The molar mass of C197H325N53O55 is 4316.08 g/mol, calculated from standard atomic weights for 197 carbon atoms, 325 hydrogen atoms, 53 nitrogen atoms and 55 oxygen atoms. The monoisotopic mass is 4313.4264 Da.
How many compounds have the formula C197H325N53O55?
CompoundList lists 1 compound with the molecular formula C197H325N53O55, including Glepaglutide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C197H325N53O55?
C197H325N53O55 has a degree of unsaturation of 62. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.