CompoundList
Molecular formula

C19H13N5O3

14 compounds have this formula on CompoundList.

Molar mass
359.34g/mol
Monoisotopic mass
359.1018Da
Atoms
40
Elements
4
Rings plus double bonds
16

The formula C19H13N5O3 describes a molecule made of 19 carbon atoms, 13 hydrogen atoms, 5 nitrogen atoms and 3 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1963.51%
    12.011 × 19 = 228.209 g/mol
  • H Hydrogen × 133.65%
    1.008 × 13 = 13.104 g/mol
  • N Nitrogen × 519.49%
    14.007 × 5 = 70.035 g/mol
  • O Oxygen × 313.36%
    15.999 × 3 = 47.997 g/mol
Look up another formula

Compounds with the formula C19H13N5O3

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 14 of 14 compounds

Frequently asked questions

What is the molar mass of C19H13N5O3?

The molar mass of C19H13N5O3 is 359.34 g/mol, calculated from standard atomic weights for 19 carbon atoms, 13 hydrogen atoms, 5 nitrogen atoms and 3 oxygen atoms. The monoisotopic mass is 359.1018 Da.

How many compounds have the formula C19H13N5O3?

CompoundList lists 14 compounds with the molecular formula C19H13N5O3, including RS 14203, 3-Nitro-N-(2-phenyl-2H-benzotriazol-5-yl)benzamide, 4-Nitro-N-(2-phenyl-2H-benzotriazol-5-yl)benzamide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C19H13N5O3?

C19H13N5O3 has a degree of unsaturation of 16. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.