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Molecular formula

C19H14BrFN4O

2 compounds have this formula on CompoundList.

Molar mass
413.25g/mol
Monoisotopic mass
412.0335Da
Atoms
40
Elements
6
Rings plus double bonds
14

The formula C19H14BrFN4O describes a molecule made of 19 carbon atoms, 14 hydrogen atoms, 1 bromine atom, 1 fluorine atom, 4 nitrogen atoms and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1955.22%
    12.011 × 19 = 228.209 g/mol
  • H Hydrogen × 143.41%
    1.008 × 14 = 14.112 g/mol
  • Br Bromine × 119.34%
    79.904 × 1 = 79.904 g/mol
  • F Fluorine × 14.60%
    18.998 × 1 = 18.998 g/mol
  • N Nitrogen × 413.56%
    14.007 × 4 = 56.028 g/mol
  • O Oxygen × 13.87%
    15.999 × 1 = 15.999 g/mol
Look up another formula

Compounds with the formula C19H14BrFN4O

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 2 of 2 compounds

N'-(5-BR-2-Fluorobenzylidene)-4,5-dihydro-1H-benzo(G)indazole-3-carbohydrazide chemical structure, C19H14BrFN4O, CAS 303106-10-7
N'-(5-BR-2-Fluorobenzylidene)-4,5-dihydro-1H-benzo(G)indazole-3-carbohydrazide
CAS 303106-10-7C19H14BrFN4O
5-(4-Fluorophenyl)-1H-pyrazole-3-carboxylic acid 2-(2-bromo-3-phenyl-2-propen-1-ylidene)hydrazide chemical structure, C19H14BrFN4O, CAS 767316-85-8
5-(4-Fluorophenyl)-1H-pyrazole-3-carboxylic acid 2-(2-bromo-3-phenyl-2-propen-1-ylidene)hydrazide
CAS 767316-85-8C19H14BrFN4O

Frequently asked questions

What is the molar mass of C19H14BrFN4O?

The molar mass of C19H14BrFN4O is 413.25 g/mol, calculated from standard atomic weights for 19 carbon atoms, 14 hydrogen atoms, 1 bromine atom, 1 fluorine atom, 4 nitrogen atoms and 1 oxygen atom. The monoisotopic mass is 412.0335 Da.

How many compounds have the formula C19H14BrFN4O?

CompoundList lists 2 compounds with the molecular formula C19H14BrFN4O, including N'-(5-BR-2-Fluorobenzylidene)-4,5-dihydro-1H-benzo(G)indazole-3-carbohydrazide, 5-(4-Fluorophenyl)-1H-pyrazole-3-carboxylic acid 2-(2-bromo-3-phenyl-2-propen-1-ylidene)hydrazide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C19H14BrFN4O?

C19H14BrFN4O has a degree of unsaturation of 14. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.