Molecular formula

C₁₉H₁₄ClFN₄OS

15 compounds have this formula on CompoundList.

Molar mass: 400.86g/mol
Monoisotopic mass: 400.0561Da
Atoms: 41
Elements: 7
Rings plus double bonds: 14

The formula C19H14ClFN4OS describes a molecule made of 19 carbon atoms, 14 hydrogen atoms, 1 chlorine atom, 1 fluorine atom, 4 nitrogen atoms, 1 oxygen atom and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

C Carbon × 1956.93%
12.011 × 19 = 228.209 g/mol
H Hydrogen × 143.52%
1.008 × 14 = 14.112 g/mol
Cl Chlorine × 18.84%
35.45 × 1 = 35.450 g/mol
F Fluorine × 14.74%
18.998 × 1 = 18.998 g/mol
N Nitrogen × 413.98%
14.007 × 4 = 56.028 g/mol
O Oxygen × 13.99%
15.999 × 1 = 15.999 g/mol
S Sulfur × 18.00%
32.06 × 1 = 32.060 g/mol

Look up another formula

Compounds with the formula C19H14ClFN4OS

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 15 of 15 compounds

N-(3-Chloro-4-fluorophenyl)-2-({5-methyl-[1,2,4]triazolo[4,3-A]quinolin-1-YL}sulfanyl)acetamide

CAS 379244-49-2C₁₉H₁₄ClFN₄OS

6-(2-Chloro-6-methylphenyl)-2-((3-fluoro-4-methylphenyl)amino)thiazolo(4,5-d)pyrimidin-7(6H)-one

CAS 2055045-42-4C₁₉H₁₄ClFN₄OS

N-(3-Chloro-4-fluorophenyl)-2-({4-methyl-[1,2,4]triazolo[4,3-A]quinolin-1-YL}sulfanyl)acetamide

CAS 510721-46-7C₁₉H₁₄ClFN₄OS

4-Chloro-N-(2-(2-(4-fluorophenyl)thiazolo[3,2-b][1,2,4]triazol-6-yl)ethyl)benzamide

CAS 894044-48-5C₁₉H₁₄ClFN₄OS

2-Chloro-N-(2-(2-(2-fluorophenyl)thiazolo[3,2-b][1,2,4]triazol-6-yl)ethyl)benzamide

CAS 895788-86-0C₁₉H₁₄ClFN₄OS

N-(5-Chloro-2-methylphenyl)-2-({8-fluoro-5H-pyrimido[5,4-b]indol-4-yl}sulfanyl)acetamide

CAS 1115997-38-0C₁₉H₁₄ClFN₄OS

2-[(2-Chloro-6-fluorobenzyl)sulfanyl]-7-(4-methoxyphenyl)[1,2,4]triazolo[1,5-a]pyrimidine

CAS 338751-45-4C₁₉H₁₄ClFN₄OS

2-Chloro-N-(2-(2-(3-fluorophenyl)thiazolo[3,2-b][1,2,4]triazol-6-yl)ethyl)benzamide

CAS 946252-40-0C₁₉H₁₄ClFN₄OS

4-Chloro-1-(4-fluorophenyl)-3-methyl-N-(thiophen-2-ylmethyl)pyrazolo[3,4-b]pyridine-5-carboxamide

CAS 1021025-11-5C₁₉H₁₄ClFN₄OS

3-((2-Chloro-6-fluorobenzyl)thio)-6-(4-methoxyphenyl)-[1,2,4]triazolo[4,3-b]pyridazine

CAS 891120-75-5C₁₉H₁₄ClFN₄OS

3-((2-Chloro-6-fluorobenzyl)thio)-6-(3-methoxyphenyl)-[1,2,4]triazolo[4,3-b]pyridazine

CAS 891096-96-1C₁₉H₁₄ClFN₄OS

3-Chloro-N-(2-(2-(4-fluorophenyl)thiazolo[3,2-b][1,2,4]triazol-6-yl)ethyl)benzamide

CAS 894044-23-6C₁₉H₁₄ClFN₄OS

N-(2-(2-(4-Chlorophenyl)thiazolo[3,2-b][1,2,4]triazol-6-yl)ethyl)-3-fluorobenzamide

CAS 894050-15-8C₁₉H₁₄ClFN₄OS

N-(2-(2-(4-Chlorophenyl)thiazolo[3,2-b][1,2,4]triazol-6-yl)ethyl)-4-fluorobenzamide

CAS 894050-49-8C₁₉H₁₄ClFN₄OS

4-Chloro-N-(2-(2-(2-fluorophenyl)thiazolo[3,2-b][1,2,4]triazol-6-yl)ethyl)benzamide

CAS 895790-09-7C₁₉H₁₄ClFN₄OS

Frequently asked questions

Still have a question?

The help centre explains buying, quotes and supplier badges step by step, or you can write to our team.

Help centre Contact us

What is the molar mass of C19H14ClFN4OS?

The molar mass of C19H14ClFN4OS is 400.86 g/mol, calculated from standard atomic weights for 19 carbon atoms, 14 hydrogen atoms, 1 chlorine atom, 1 fluorine atom, 4 nitrogen atoms, 1 oxygen atom and 1 sulfur atom. The monoisotopic mass is 400.0561 Da.

How many compounds have the formula C19H14ClFN4OS?

CompoundList lists 15 compounds with the molecular formula C19H14ClFN4OS, including N-(3-Chloro-4-fluorophenyl)-2-({5-methyl-[1,2,4]triazolo[4,3-A]quinolin-1-YL}sulfanyl)acetamide, 6-(2-Chloro-6-methylphenyl)-2-((3-fluoro-4-methylphenyl)amino)thiazolo(4,5-d)pyrimidin-7(6H)-one, N-(3-Chloro-4-fluorophenyl)-2-({4-methyl-[1,2,4]triazolo[4,3-A]quinolin-1-YL}sulfanyl)acetamide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C19H14ClFN4OS?

C19H14ClFN4OS has a degree of unsaturation of 14. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.