C19H15F3IP
1 compound has this formula on CompoundList.
- Molar mass
- 458.20g/mol
- Monoisotopic mass
- 457.9908Da
- Atoms
- 39
- Elements
- 5
- Rings plus double bonds
- 11
The formula C19H15F3IP describes a molecule made of 19 carbon atoms, 15 hydrogen atoms, 3 fluorine atoms, 1 iodine atom and 1 phosphorus atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1949.81%12.011 × 19 = 228.209 g/mol
- H Hydrogen × 153.30%1.008 × 15 = 15.120 g/mol
- F Fluorine × 312.44%18.998 × 3 = 56.994 g/mol
- I Iodine × 127.70%126.9 × 1 = 126.900 g/mol
- P Phosphorus × 16.76%30.974 × 1 = 30.974 g/mol
Compounds with the formula C19H15F3IP
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C19H15F3IP?
The molar mass of C19H15F3IP is 458.20 g/mol, calculated from standard atomic weights for 19 carbon atoms, 15 hydrogen atoms, 3 fluorine atoms, 1 iodine atom and 1 phosphorus atom. The monoisotopic mass is 457.9908 Da.
How many compounds have the formula C19H15F3IP?
CompoundList lists 1 compound with the molecular formula C19H15F3IP, including Methyltris(4-fluorophenyl)phosphonium iodide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C19H15F3IP?
C19H15F3IP has a degree of unsaturation of 11. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.