CompoundList
Molecular formula

C19H21FN4O5S

11 compounds have this formula on CompoundList.

Molar mass
436.46g/mol
Monoisotopic mass
436.1217Da
Atoms
51
Elements
6
Rings plus double bonds
11

The formula C19H21FN4O5S describes a molecule made of 19 carbon atoms, 21 hydrogen atoms, 1 fluorine atom, 4 nitrogen atoms, 5 oxygen atoms and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1952.29%
    12.011 × 19 = 228.209 g/mol
  • H Hydrogen × 214.85%
    1.008 × 21 = 21.168 g/mol
  • F Fluorine × 14.35%
    18.998 × 1 = 18.998 g/mol
  • N Nitrogen × 412.84%
    14.007 × 4 = 56.028 g/mol
  • O Oxygen × 518.33%
    15.999 × 5 = 79.995 g/mol
  • S Sulfur × 17.35%
    32.06 × 1 = 32.060 g/mol
Look up another formula

Compounds with the formula C19H21FN4O5S

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 11 of 11 compounds

Frequently asked questions

What is the molar mass of C19H21FN4O5S?

The molar mass of C19H21FN4O5S is 436.46 g/mol, calculated from standard atomic weights for 19 carbon atoms, 21 hydrogen atoms, 1 fluorine atom, 4 nitrogen atoms, 5 oxygen atoms and 1 sulfur atom. The monoisotopic mass is 436.1217 Da.

How many compounds have the formula C19H21FN4O5S?

CompoundList lists 11 compounds with the molecular formula C19H21FN4O5S, including N1-((3-((4-fluorophenyl)sulfonyl)-1,3-oxazinan-2-yl)methyl)-N2-(pyridin-4-ylmethyl)oxalamide, N1-((3-((4-fluorophenyl)sulfonyl)-1,3-oxazinan-2-yl)methyl)-N2-(pyridin-2-ylmethyl)oxalamide, N1-((3-((4-fluorophenyl)sulfonyl)-1,3-oxazinan-2-yl)methyl)-N2-(pyridin-3-ylmethyl)oxalamide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C19H21FN4O5S?

C19H21FN4O5S has a degree of unsaturation of 11. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.