CompoundList
Molecular formula

C19H22FN3

3 compounds have this formula on CompoundList.

Molar mass
311.40g/mol
Monoisotopic mass
311.1798Da
Atoms
45
Elements
4
Rings plus double bonds
10

The formula C19H22FN3 describes a molecule made of 19 carbon atoms, 22 hydrogen atoms, 1 fluorine atom and 3 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1973.28%
    12.011 × 19 = 228.209 g/mol
  • H Hydrogen × 227.12%
    1.008 × 22 = 22.176 g/mol
  • F Fluorine × 16.10%
    18.998 × 1 = 18.998 g/mol
  • N Nitrogen × 313.49%
    14.007 × 3 = 42.021 g/mol
Look up another formula

Compounds with the formula C19H22FN3

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 3 of 3 compounds

Frequently asked questions

What is the molar mass of C19H22FN3?

The molar mass of C19H22FN3 is 311.40 g/mol, calculated from standard atomic weights for 19 carbon atoms, 22 hydrogen atoms, 1 fluorine atom and 3 nitrogen atoms. The monoisotopic mass is 311.1798 Da.

How many compounds have the formula C19H22FN3?

CompoundList lists 3 compounds with the molecular formula C19H22FN3, including N-(3-Fluorobenzylidene)-4-(4-methylbenzyl)-1-piperazinamine, 1H-Pyrrolo[2,3-c]pyridin-7-amine,N-[(4-fluoro-2-methylphenyl)methyl]-2-methyl-1-propyl-, 1H-Pyrrolo[2,3-c]pyridin-7-amine,1-ethyl-N-[(4-fluoro-2-methylphenyl)methyl]-2,3-dimethyl-. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C19H22FN3?

C19H22FN3 has a degree of unsaturation of 10. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.