CompoundList
Molecular formula

C20H13F3N2O7

1 compound has this formula on CompoundList.

Molar mass
450.32g/mol
Monoisotopic mass
450.0675Da
Atoms
45
Elements
5
Rings plus double bonds
14

The formula C20H13F3N2O7 describes a molecule made of 20 carbon atoms, 13 hydrogen atoms, 3 fluorine atoms, 2 nitrogen atoms and 7 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2053.34%
    12.011 × 20 = 240.220 g/mol
  • H Hydrogen × 132.91%
    1.008 × 13 = 13.104 g/mol
  • F Fluorine × 312.66%
    18.998 × 3 = 56.994 g/mol
  • N Nitrogen × 26.22%
    14.007 × 2 = 28.014 g/mol
  • O Oxygen × 724.87%
    15.999 × 7 = 111.993 g/mol
Look up another formula

Compounds with the formula C20H13F3N2O7

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C20H13F3N2O7?

The molar mass of C20H13F3N2O7 is 450.32 g/mol, calculated from standard atomic weights for 20 carbon atoms, 13 hydrogen atoms, 3 fluorine atoms, 2 nitrogen atoms and 7 oxygen atoms. The monoisotopic mass is 450.0675 Da.

How many compounds have the formula C20H13F3N2O7?

CompoundList lists 1 compound with the molecular formula C20H13F3N2O7, including 3-[2,6-Dinitro-4-(trifluoromethyl)phenoxy]-7,8,9,10-tetrahydrobenzo[c]chromen-6-one. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C20H13F3N2O7?

C20H13F3N2O7 has a degree of unsaturation of 14. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.