C20H14FN5
3 compounds have this formula on CompoundList.
- Molar mass
- 343.37g/mol
- Monoisotopic mass
- 343.1233Da
- Atoms
- 40
- Elements
- 4
- Rings plus double bonds
- 16
The formula C20H14FN5 describes a molecule made of 20 carbon atoms, 14 hydrogen atoms, 1 fluorine atom and 5 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2069.96%12.011 × 20 = 240.220 g/mol
- H Hydrogen × 144.11%1.008 × 14 = 14.112 g/mol
- F Fluorine × 15.53%18.998 × 1 = 18.998 g/mol
- N Nitrogen × 520.40%14.007 × 5 = 70.035 g/mol
Compounds with the formula C20H14FN5
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 3 of 3 compounds
![Benzonitrile, 4-[7-[[(4-fluorophenyl)methyl]amino][1,2,4]triazolo[1,5-a]pyridin-5-yl]- chemical structure, C20H14FN5, CAS 2009344-28-7](/s/DDBNRFRBPGDKLB-UHFFFAOYSA-N.svg)
![6-Amino-4-(2-fluorophenyl)-3-methyl-1-phenyl-1H-pyrazolo[3,4-b]pyridine-5-carbonitrile chemical structure, C20H14FN5, CAS 1103593-92-5](/s/VEKGBTFEVBMSLL-UHFFFAOYSA-N.svg)
Frequently asked questions
What is the molar mass of C20H14FN5?
The molar mass of C20H14FN5 is 343.37 g/mol, calculated from standard atomic weights for 20 carbon atoms, 14 hydrogen atoms, 1 fluorine atom and 5 nitrogen atoms. The monoisotopic mass is 343.1233 Da.
How many compounds have the formula C20H14FN5?
CompoundList lists 3 compounds with the molecular formula C20H14FN5, including RefChem:380561, Benzonitrile, 4-[7-[[(4-fluorophenyl)methyl]amino][1,2,4]triazolo[1,5-a]pyridin-5-yl]-, 6-Amino-4-(2-fluorophenyl)-3-methyl-1-phenyl-1H-pyrazolo[3,4-b]pyridine-5-carbonitrile. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C20H14FN5?
C20H14FN5 has a degree of unsaturation of 16. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.