C20H22N6O5S3
1 compound has this formula on CompoundList.
- Molar mass
- 522.61g/mol
- Monoisotopic mass
- 522.0814Da
- Atoms
- 56
- Elements
- 5
- Rings plus double bonds
- 13
The formula C20H22N6O5S3 describes a molecule made of 20 carbon atoms, 22 hydrogen atoms, 6 nitrogen atoms, 5 oxygen atoms and 3 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2045.97%12.011 × 20 = 240.220 g/mol
- H Hydrogen × 224.24%1.008 × 22 = 22.176 g/mol
- N Nitrogen × 616.08%14.007 × 6 = 84.042 g/mol
- O Oxygen × 515.31%15.999 × 5 = 79.995 g/mol
- S Sulfur × 318.40%32.06 × 3 = 96.180 g/mol
Compounds with the formula C20H22N6O5S3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C20H22N6O5S3?
The molar mass of C20H22N6O5S3 is 522.61 g/mol, calculated from standard atomic weights for 20 carbon atoms, 22 hydrogen atoms, 6 nitrogen atoms, 5 oxygen atoms and 3 sulfur atoms. The monoisotopic mass is 522.0814 Da.
How many compounds have the formula C20H22N6O5S3?
CompoundList lists 1 compound with the molecular formula C20H22N6O5S3, including Tenuecyclamide D. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C20H22N6O5S3?
C20H22N6O5S3 has a degree of unsaturation of 13. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.