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Molecular formula

C20H4F24O8Zr

1 compound has this formula on CompoundList.

Molar mass
919.42g/mol
Monoisotopic mass
917.8570Da
Atoms
57
Elements
5

The formula C20H4F24O8Zr describes a molecule made of 20 carbon atoms, 4 hydrogen atoms, 24 fluorine atoms, 8 oxygen atoms and 1 zirconium atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2026.13%
    12.011 × 20 = 240.220 g/mol
  • H Hydrogen × 40.44%
    1.008 × 4 = 4.032 g/mol
  • F Fluorine × 2449.59%
    18.998 × 24 = 455.952 g/mol
  • O Oxygen × 813.92%
    15.999 × 8 = 127.992 g/mol
  • Zr Zirconium × 19.92%
    91.224 × 1 = 91.224 g/mol
Look up another formula

Compounds with the formula C20H4F24O8Zr

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Zirconium(4+) tetrakis[(2Z)-1,1,1,5,5,5-hexafluoro-4-oxo-2-penten-2-olate] chemical structure, C20H4F24O8Zr
Zirconium(4+) tetrakis[(2Z)-1,1,1,5,5,5-hexafluoro-4-oxo-2-penten-2-olate]
C20H4F24O8Zr

Frequently asked questions

What is the molar mass of C20H4F24O8Zr?

The molar mass of C20H4F24O8Zr is 919.42 g/mol, calculated from standard atomic weights for 20 carbon atoms, 4 hydrogen atoms, 24 fluorine atoms, 8 oxygen atoms and 1 zirconium atom. The monoisotopic mass is 917.8570 Da.

How many compounds have the formula C20H4F24O8Zr?

CompoundList lists 1 compound with the molecular formula C20H4F24O8Zr, including Zirconium(4+) tetrakis[(2Z)-1,1,1,5,5,5-hexafluoro-4-oxo-2-penten-2-olate]. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.