CompoundList
Molecular formula

C21H13FN4

4 compounds have this formula on CompoundList.

Molar mass
340.36g/mol
Monoisotopic mass
340.1124Da
Atoms
39
Elements
4
Rings plus double bonds
17

The formula C21H13FN4 describes a molecule made of 21 carbon atoms, 13 hydrogen atoms, 1 fluorine atom and 4 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2174.11%
    12.011 × 21 = 252.231 g/mol
  • H Hydrogen × 133.85%
    1.008 × 13 = 13.104 g/mol
  • F Fluorine × 15.58%
    18.998 × 1 = 18.998 g/mol
  • N Nitrogen × 416.46%
    14.007 × 4 = 56.028 g/mol
Look up another formula

Compounds with the formula C21H13FN4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 4 of 4 compounds

Frequently asked questions

What is the molar mass of C21H13FN4?

The molar mass of C21H13FN4 is 340.36 g/mol, calculated from standard atomic weights for 21 carbon atoms, 13 hydrogen atoms, 1 fluorine atom and 4 nitrogen atoms. The monoisotopic mass is 340.1124 Da.

How many compounds have the formula C21H13FN4?

CompoundList lists 4 compounds with the molecular formula C21H13FN4, including 8-Fluoro-4-(pyridin-3-yl)-6-{1H-pyrrolo[2,3-b]pyridin-3-yl}quinoline, 2-(4-Cyanophenyl)4-(4-fluorophenyl)-5-(4-pyridyl)-1H-imidazole, 2-Amino-6-(4-fluorophenyl)-4-phenylcyclohexa-2,4-diene-1,1,3-tricarbonitrile. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C21H13FN4?

C21H13FN4 has a degree of unsaturation of 17. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.