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Molecular formula

C21H15FN4S

2 compounds have this formula on CompoundList.

Molar mass
374.44g/mol
Monoisotopic mass
374.1001Da
Atoms
42
Elements
5
Rings plus double bonds
16

The formula C21H15FN4S describes a molecule made of 21 carbon atoms, 15 hydrogen atoms, 1 fluorine atom, 4 nitrogen atoms and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2167.36%
    12.011 × 21 = 252.231 g/mol
  • H Hydrogen × 154.04%
    1.008 × 15 = 15.120 g/mol
  • F Fluorine × 15.07%
    18.998 × 1 = 18.998 g/mol
  • N Nitrogen × 414.96%
    14.007 × 4 = 56.028 g/mol
  • S Sulfur × 18.56%
    32.06 × 1 = 32.060 g/mol
Look up another formula

Compounds with the formula C21H15FN4S

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 2 of 2 compounds

4-(((1,1'-Biphenyl)-4-ylmethylene)amino)-5-(4-F-PH)-4H-1,2,4-triazole-3-thiol chemical structure, C21H15FN4S, CAS 573929-61-0
4-(((1,1'-Biphenyl)-4-ylmethylene)amino)-5-(4-F-PH)-4H-1,2,4-triazole-3-thiol
CAS 573929-61-0C21H15FN4S
4-(((1,1'-Biphenyl)-4-ylmethylene)amino)-5-(2-F-PH)-4H-1,2,4-triazole-3-thiol chemical structure, C21H15FN4S, CAS 675843-76-2
4-(((1,1'-Biphenyl)-4-ylmethylene)amino)-5-(2-F-PH)-4H-1,2,4-triazole-3-thiol
CAS 675843-76-2C21H15FN4S

Frequently asked questions

What is the molar mass of C21H15FN4S?

The molar mass of C21H15FN4S is 374.44 g/mol, calculated from standard atomic weights for 21 carbon atoms, 15 hydrogen atoms, 1 fluorine atom, 4 nitrogen atoms and 1 sulfur atom. The monoisotopic mass is 374.1001 Da.

How many compounds have the formula C21H15FN4S?

CompoundList lists 2 compounds with the molecular formula C21H15FN4S, including 4-(((1,1'-Biphenyl)-4-ylmethylene)amino)-5-(4-F-PH)-4H-1,2,4-triazole-3-thiol, 4-(((1,1'-Biphenyl)-4-ylmethylene)amino)-5-(2-F-PH)-4H-1,2,4-triazole-3-thiol. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C21H15FN4S?

C21H15FN4S has a degree of unsaturation of 16. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.