CompoundList
Molecular formula

C21H16F4

2 compounds have this formula on CompoundList.

Molar mass
344.35g/mol
Monoisotopic mass
344.1188Da
Atoms
41
Elements
3
Rings plus double bonds
12

The formula C21H16F4 describes a molecule made of 21 carbon atoms, 16 hydrogen atoms and 4 fluorine atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2173.25%
    12.011 × 21 = 252.231 g/mol
  • H Hydrogen × 164.68%
    1.008 × 16 = 16.128 g/mol
  • F Fluorine × 422.07%
    18.998 × 4 = 75.992 g/mol
Look up another formula

Compounds with the formula C21H16F4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 2 of 2 compounds

Frequently asked questions

What is the molar mass of C21H16F4?

The molar mass of C21H16F4 is 344.35 g/mol, calculated from standard atomic weights for 21 carbon atoms, 16 hydrogen atoms and 4 fluorine atoms. The monoisotopic mass is 344.1188 Da.

How many compounds have the formula C21H16F4?

CompoundList lists 2 compounds with the molecular formula C21H16F4, including 3-BB(F)B(F,F)-F, 4-Propyl-2,3'',4'',5''-tetrafluoro-1,1':4',1''-Terphenyl. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C21H16F4?

C21H16F4 has a degree of unsaturation of 12. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.