C21H16FN7O
2 compounds have this formula on CompoundList.
- Molar mass
- 401.40g/mol
- Monoisotopic mass
- 401.1400Da
- Atoms
- 46
- Elements
- 5
- Rings plus double bonds
- 17
The formula C21H16FN7O describes a molecule made of 21 carbon atoms, 16 hydrogen atoms, 1 fluorine atom, 7 nitrogen atoms and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2162.84%12.011 × 21 = 252.231 g/mol
- H Hydrogen × 164.02%1.008 × 16 = 16.128 g/mol
- F Fluorine × 14.73%18.998 × 1 = 18.998 g/mol
- N Nitrogen × 724.43%14.007 × 7 = 98.049 g/mol
- O Oxygen × 13.99%15.999 × 1 = 15.999 g/mol
Compounds with the formula C21H16FN7O
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 2 of 2 compounds
Frequently asked questions
What is the molar mass of C21H16FN7O?
The molar mass of C21H16FN7O is 401.40 g/mol, calculated from standard atomic weights for 21 carbon atoms, 16 hydrogen atoms, 1 fluorine atom, 7 nitrogen atoms and 1 oxygen atom. The monoisotopic mass is 401.1400 Da.
How many compounds have the formula C21H16FN7O?
CompoundList lists 2 compounds with the molecular formula C21H16FN7O, including Acalisib, (S)-2-(1-(9H-Purin-6-ylamino)ethyl)-5-fluoro-3-phenylquinazolin-4(3H)-one. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C21H16FN7O?
C21H16FN7O has a degree of unsaturation of 17. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.