C21H22ClFN4O3
4 compounds have this formula on CompoundList.
- Molar mass
- 432.88g/mol
- Monoisotopic mass
- 440.1867Da
- Atoms
- 52
- Elements
- 6
- Rings plus double bonds
- 12
The formula C21H22ClFN4O3 describes a molecule made of 21 carbon atoms, 22 hydrogen atoms, 1 chlorine atom, 1 fluorine atom, 4 nitrogen atoms and 3 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2158.27%12.011 × 21 = 252.231 g/mol
- H Hydrogen × 225.12%1.008 × 22 = 22.176 g/mol
- Cl Chlorine × 18.19%35.45 × 1 = 35.450 g/mol
- F Fluorine × 14.39%18.998 × 1 = 18.998 g/mol
- N Nitrogen × 412.94%14.007 × 4 = 56.028 g/mol
- O Oxygen × 311.09%15.999 × 3 = 47.997 g/mol
Compounds with the formula C21H22ClFN4O3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 4 of 4 compounds
Frequently asked questions
What is the molar mass of C21H22ClFN4O3?
The molar mass of C21H22ClFN4O3 is 432.88 g/mol, calculated from standard atomic weights for 21 carbon atoms, 22 hydrogen atoms, 1 chlorine atom, 1 fluorine atom, 4 nitrogen atoms and 3 oxygen atoms. The monoisotopic mass is 440.1867 Da.
How many compounds have the formula C21H22ClFN4O3?
CompoundList lists 4 compounds with the molecular formula C21H22ClFN4O3, including O-Desmethyl gefitinib, Pradofloxacin hydrochloride, O-Desmethyl gefitinib D8. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C21H22ClFN4O3?
C21H22ClFN4O3 has a degree of unsaturation of 12. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.