CompoundList
Molecular formula

C21H23ClN2O7

8 compounds have this formula on CompoundList.

Molar mass
450.87g/mol
Monoisotopic mass
450.1194Da
Atoms
54
Elements
5
Rings plus double bonds
11

The formula C21H23ClN2O7 describes a molecule made of 21 carbon atoms, 23 hydrogen atoms, 1 chlorine atom, 2 nitrogen atoms and 7 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2155.94%
    12.011 × 21 = 252.231 g/mol
  • H Hydrogen × 235.14%
    1.008 × 23 = 23.184 g/mol
  • Cl Chlorine × 17.86%
    35.45 × 1 = 35.450 g/mol
  • N Nitrogen × 26.21%
    14.007 × 2 = 28.014 g/mol
  • O Oxygen × 724.84%
    15.999 × 7 = 111.993 g/mol
Look up another formula

Compounds with the formula C21H23ClN2O7

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 8 of 8 compounds

Frequently asked questions

What is the molar mass of C21H23ClN2O7?

The molar mass of C21H23ClN2O7 is 450.87 g/mol, calculated from standard atomic weights for 21 carbon atoms, 23 hydrogen atoms, 1 chlorine atom, 2 nitrogen atoms and 7 oxygen atoms. The monoisotopic mass is 450.1194 Da.

How many compounds have the formula C21H23ClN2O7?

CompoundList lists 8 compounds with the molecular formula C21H23ClN2O7, including Sancycline hydrochloride, epi-Sancycline Hydrochloride, epi-Sancycline. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C21H23ClN2O7?

C21H23ClN2O7 has a degree of unsaturation of 11. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.