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Molecular formula

C21H24F3N7O

2 compounds have this formula on CompoundList.

Molar mass
447.47g/mol
Monoisotopic mass
447.1994Da
Atoms
56
Elements
5
Rings plus double bonds
12

The formula C21H24F3N7O describes a molecule made of 21 carbon atoms, 24 hydrogen atoms, 3 fluorine atoms, 7 nitrogen atoms and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2156.37%
    12.011 × 21 = 252.231 g/mol
  • H Hydrogen × 245.41%
    1.008 × 24 = 24.192 g/mol
  • F Fluorine × 312.74%
    18.998 × 3 = 56.994 g/mol
  • N Nitrogen × 721.91%
    14.007 × 7 = 98.049 g/mol
  • O Oxygen × 13.58%
    15.999 × 1 = 15.999 g/mol
Look up another formula

Compounds with the formula C21H24F3N7O

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 2 of 2 compounds

Gsk-2256294 chemical structure, C21H24F3N7O, CAS 1142090-23-0
Gsk-2256294
CAS 1142090-23-0C21H24F3N7O
2-Cyclopropyl-4,5-dimethyl-6-({1-[3-(trifluoromethyl)-[1,2,4]triazolo[4,3-b]pyridazin-6-yl]piperidin-4-yl}methoxy)pyrimidine chemical structure, C21H24F3N7O, CAS 2742044-38-6
2-Cyclopropyl-4,5-dimethyl-6-({1-[3-(trifluoromethyl)-[1,2,4]triazolo[4,3-b]pyridazin-6-yl]piperidin-4-yl}methoxy)pyrimidine
CAS 2742044-38-6C21H24F3N7O

Frequently asked questions

What is the molar mass of C21H24F3N7O?

The molar mass of C21H24F3N7O is 447.47 g/mol, calculated from standard atomic weights for 21 carbon atoms, 24 hydrogen atoms, 3 fluorine atoms, 7 nitrogen atoms and 1 oxygen atom. The monoisotopic mass is 447.1994 Da.

How many compounds have the formula C21H24F3N7O?

CompoundList lists 2 compounds with the molecular formula C21H24F3N7O, including Gsk-2256294, 2-Cyclopropyl-4,5-dimethyl-6-({1-[3-(trifluoromethyl)-[1,2,4]triazolo[4,3-b]pyridazin-6-yl]piperidin-4-yl}methoxy)pyrimidine. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C21H24F3N7O?

C21H24F3N7O has a degree of unsaturation of 12. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.