CompoundList
Molecular formula

C22H15F3N2O7S

1 compound has this formula on CompoundList.

Molar mass
508.42g/mol
Monoisotopic mass
508.0552Da
Atoms
50
Elements
6
Rings plus double bonds
15

The formula C22H15F3N2O7S describes a molecule made of 22 carbon atoms, 15 hydrogen atoms, 3 fluorine atoms, 2 nitrogen atoms, 7 oxygen atoms and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2251.97%
    12.011 × 22 = 264.242 g/mol
  • H Hydrogen × 152.97%
    1.008 × 15 = 15.120 g/mol
  • F Fluorine × 311.21%
    18.998 × 3 = 56.994 g/mol
  • N Nitrogen × 25.51%
    14.007 × 2 = 28.014 g/mol
  • O Oxygen × 722.03%
    15.999 × 7 = 111.993 g/mol
  • S Sulfur × 16.31%
    32.06 × 1 = 32.060 g/mol
Look up another formula

Compounds with the formula C22H15F3N2O7S

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C22H15F3N2O7S?

The molar mass of C22H15F3N2O7S is 508.42 g/mol, calculated from standard atomic weights for 22 carbon atoms, 15 hydrogen atoms, 3 fluorine atoms, 2 nitrogen atoms, 7 oxygen atoms and 1 sulfur atom. The monoisotopic mass is 508.0552 Da.

How many compounds have the formula C22H15F3N2O7S?

CompoundList lists 1 compound with the molecular formula C22H15F3N2O7S, including Linzagolix. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C22H15F3N2O7S?

C22H15F3N2O7S has a degree of unsaturation of 15. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.