CompoundList
Molecular formula

C23H24FNO4

14 compounds have this formula on CompoundList.

Molar mass
397.45g/mol
Monoisotopic mass
397.1689Da
Atoms
53
Elements
5
Rings plus double bonds
12

The formula C23H24FNO4 describes a molecule made of 23 carbon atoms, 24 hydrogen atoms, 1 fluorine atom, 1 nitrogen atom and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2369.51%
    12.011 × 23 = 276.253 g/mol
  • H Hydrogen × 246.09%
    1.008 × 24 = 24.192 g/mol
  • F Fluorine × 14.78%
    18.998 × 1 = 18.998 g/mol
  • N Nitrogen × 13.52%
    14.007 × 1 = 14.007 g/mol
  • O Oxygen × 416.10%
    15.999 × 4 = 63.996 g/mol
Look up another formula

Compounds with the formula C23H24FNO4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 14 of 14 compounds

Frequently asked questions

What is the molar mass of C23H24FNO4?

The molar mass of C23H24FNO4 is 397.45 g/mol, calculated from standard atomic weights for 23 carbon atoms, 24 hydrogen atoms, 1 fluorine atom, 1 nitrogen atom and 4 oxygen atoms. The monoisotopic mass is 397.1689 Da.

How many compounds have the formula C23H24FNO4?

CompoundList lists 14 compounds with the molecular formula C23H24FNO4, including Ici D2138, 3-(1-(((9H-Fluoren-9-yl)methoxy)carbonyl)piperidin-4-yl)-2-fluoropropanoic acid, Fluvastatin EP impurity C. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C23H24FNO4?

C23H24FNO4 has a degree of unsaturation of 12. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.