C23H35F
3 compounds have this formula on CompoundList.
- Molar mass
- 330.53g/mol
- Monoisotopic mass
- 330.2723Da
- Atoms
- 59
- Elements
- 3
- Rings plus double bonds
- 6
The formula C23H35F describes a molecule made of 23 carbon atoms, 35 hydrogen atoms and 1 fluorine atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2383.58%12.011 × 23 = 276.253 g/mol
- H Hydrogen × 3510.67%1.008 × 35 = 35.280 g/mol
- F Fluorine × 15.75%18.998 × 1 = 18.998 g/mol
Compounds with the formula C23H35F
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 3 of 3 compounds
![(1r,1's,4r,4'r)-4-[2-(4-Fluorophenyl)ethyl]-4'-propyl-1,1'-bi(cyclohexane) chemical structure, C23H35F, CAS 97941-21-4](/s/FNIPGBFUEZMVHZ-UHFFFAOYSA-N.svg)
Frequently asked questions
What is the molar mass of C23H35F?
The molar mass of C23H35F is 330.53 g/mol, calculated from standard atomic weights for 23 carbon atoms, 35 hydrogen atoms and 1 fluorine atom. The monoisotopic mass is 330.2723 Da.
How many compounds have the formula C23H35F?
CompoundList lists 3 compounds with the molecular formula C23H35F, including (1r,1's,4r,4'r)-4-[2-(4-Fluorophenyl)ethyl]-4'-propyl-1,1'-bi(cyclohexane), 4-(4-Fluorophenyl)-4'-pentyl-1,1'-bi(cyclohexane), 1-Fluoro-4-(trans-4-(2-(trans-4-propylcyclohexyl)ethyl)cyclohexyl)benzene. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C23H35F?
C23H35F has a degree of unsaturation of 6. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.