CompoundList
Molecular formula

C23H35N3O2S4

1 compound has this formula on CompoundList.

Molar mass
513.79g/mol
Monoisotopic mass
513.1612Da
Atoms
67
Elements
5
Rings plus double bonds
8

The formula C23H35N3O2S4 describes a molecule made of 23 carbon atoms, 35 hydrogen atoms, 3 nitrogen atoms, 2 oxygen atoms and 4 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2353.77%
    12.011 × 23 = 276.253 g/mol
  • H Hydrogen × 356.87%
    1.008 × 35 = 35.280 g/mol
  • N Nitrogen × 38.18%
    14.007 × 3 = 42.021 g/mol
  • O Oxygen × 26.23%
    15.999 × 2 = 31.998 g/mol
  • S Sulfur × 424.96%
    32.06 × 4 = 128.240 g/mol
Look up another formula

Compounds with the formula C23H35N3O2S4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C23H35N3O2S4?

The molar mass of C23H35N3O2S4 is 513.79 g/mol, calculated from standard atomic weights for 23 carbon atoms, 35 hydrogen atoms, 3 nitrogen atoms, 2 oxygen atoms and 4 sulfur atoms. The monoisotopic mass is 513.1612 Da.

How many compounds have the formula C23H35N3O2S4?

CompoundList lists 1 compound with the molecular formula C23H35N3O2S4, including 10-[3-(Dansylamido)propyl]-1,4,7-trithia-10-azacyclododecane. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C23H35N3O2S4?

C23H35N3O2S4 has a degree of unsaturation of 8. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.