CompoundList
Molecular formula

C23H42ClNO

4 compounds have this formula on CompoundList.

Molar mass
384.05g/mol
Monoisotopic mass
383.2955Da
Atoms
68
Elements
5
Rings plus double bonds
3

The formula C23H42ClNO describes a molecule made of 23 carbon atoms, 42 hydrogen atoms, 1 chlorine atom, 1 nitrogen atom and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 2371.93%
    12.011 × 23 = 276.253 g/mol
  • H Hydrogen × 4211.02%
    1.008 × 42 = 42.336 g/mol
  • Cl Chlorine × 19.23%
    35.45 × 1 = 35.450 g/mol
  • N Nitrogen × 13.65%
    14.007 × 1 = 14.007 g/mol
  • O Oxygen × 14.17%
    15.999 × 1 = 15.999 g/mol
Look up another formula

Compounds with the formula C23H42ClNO

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 4 of 4 compounds

Frequently asked questions

What is the molar mass of C23H42ClNO?

The molar mass of C23H42ClNO is 384.05 g/mol, calculated from standard atomic weights for 23 carbon atoms, 42 hydrogen atoms, 1 chlorine atom, 1 nitrogen atom and 1 oxygen atom. The monoisotopic mass is 383.2955 Da.

How many compounds have the formula C23H42ClNO?

CompoundList lists 4 compounds with the molecular formula C23H42ClNO, including Benzenemethanaminium, N-[2-(dodecyloxy)ethyl]-N,N-dimethyl-, chloride, (p-Dodecylbenzyl)(2-hydroxyethyl)dimethylammonium chloride, 2-[(Diethylamino)methyl]-1-phenyldodecan-1-ol--hydrogen chloride (1/1). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C23H42ClNO?

C23H42ClNO has a degree of unsaturation of 3. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.