C24H21Br3I3N5O8
1 compound has this formula on CompoundList.
- Molar mass
- 1127.87g/mol
- Monoisotopic mass
- 1124.6074Da
- Atoms
- 64
- Elements
- 6
- Rings plus double bonds
- 14
The formula C24H21Br3I3N5O8 describes a molecule made of 24 carbon atoms, 21 hydrogen atoms, 3 bromine atoms, 3 iodine atoms, 5 nitrogen atoms and 8 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 2425.56%12.011 × 24 = 288.264 g/mol
- H Hydrogen × 211.88%1.008 × 21 = 21.168 g/mol
- Br Bromine × 321.25%79.904 × 3 = 239.712 g/mol
- I Iodine × 333.75%126.9 × 3 = 380.700 g/mol
- N Nitrogen × 56.21%14.007 × 5 = 70.035 g/mol
- O Oxygen × 811.35%15.999 × 8 = 127.992 g/mol
Compounds with the formula C24H21Br3I3N5O8
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C24H21Br3I3N5O8?
The molar mass of C24H21Br3I3N5O8 is 1127.87 g/mol, calculated from standard atomic weights for 24 carbon atoms, 21 hydrogen atoms, 3 bromine atoms, 3 iodine atoms, 5 nitrogen atoms and 8 oxygen atoms. The monoisotopic mass is 1124.6074 Da.
How many compounds have the formula C24H21Br3I3N5O8?
CompoundList lists 1 compound with the molecular formula C24H21Br3I3N5O8, including Ioxabrolic acid. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C24H21Br3I3N5O8?
C24H21Br3I3N5O8 has a degree of unsaturation of 14. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.